[HackerRank][Python3] Sherlock and the Valid String
2018. 7. 15. 02:33 |
프로그래밍/HackerRank
Problem :
https://www.hackerrank.com/challenges/sherlock-and-valid-string/problem
My Solution :
#!/usr/bin/env python3
from collections import defaultdict
def isValid(s):
char_dic, count_dic = defaultdict(int), defaultdict(int)
for char in s:
char_dic[char] += 1
for count in char_dic.values():
count_dic[count] += 1
if len(count_dic) == 1:
return 'YES'
if len(count_dic) > 2:
return 'NO'
m, M = sorted(count_dic)
if count_dic[1] == 1:
return 'YES'
if M - m == 1 and count_dic[M] == 1:
return 'YES'
return 'NO'
s = input().strip()
result = isValid(s)
print(result)
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